11.3 - char * to uint8_t *

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In the following example there is an implicit conversion from (char *) to (uint8_t *):

Code:

extern void print(const uint8_t *text);

int main(void)
{
    print("Some text");
}

Am I correct in thinking that this is compliant? Or does the exception to rule 11.3 only apply when conversions are explicit?

Thanks.