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6.2 and switch/case labels
#1
I'm not 100% sure on the interpretation of rule 6.2 when it comes to using "unsigned char" values as labels for switch case.

Example:

Code:
const uint8_t CONSTANT_ONE = 12U;
const uint8_t CONSTANT_TWO = 34U;

uint8_t value = foo();

switch (value)
{
case CONSTANT_ONE:
  [...]
   break;
case CONSTANT_TWO:
  [...]
   break;
default:
  [...]
   break;
}

For each of the "case " lines PC-lint (from V9.00j on) complains about a "Disallowed use of non-numeric value in a case label".
I would have considered defining and using the contants as "storage and use of numeric values" as described in 6.2.
I also can not find a similar limitation in MISRA-C 2012. Though I might not have looked deeply enough as I only have it in printed form.

Thanks for any feedback you might have on this.
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#2
We shall divide our response into 3 sections.

1. This code contains a constraint error and so will violate Rule 1.1. Both C90 6.6.4.2 and C99 6.8.4.2(3) list in their constraint section that the case label "shall be an integer constant expression". A const object is not an "integer constant expression" in C. The code would be compliant with C if the following had been used
#define CONSTANT_ONE 12U
It could be that this is what the PC-lint message is referring to, since CONSTANT_ONE in the original example is an object not a numeric value.

2. Assuming uint8_t has been defined as "unsigned char", there is no violation of 6.2 in this example. If uint8_t had been defined as plain "char", then rule 6.1 would have been violated in the initialisations of CONSTANT_ONE and CONSTANT_TWO.

3. MISRA-C:2004 rules 6.1 and 6.2 are covered by the essential type rules R.10.1 - R.10.8 of MISRA C:2012.
Posted by and on behalf of the MISRA C Working Group
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