why adding #define contsants for initializing a const is breaking rule 10.3 ?

[Francois]

Hi
you just have to cast your data. 2 solutions:
Code_1:

Code:

// this constrains the use of the define
#define CONST1 ((uint16_t)556U)
uint16_t const MY_var1 = CONST1;

Code_2:

Code:

#define CONST1 556U
uint16_t const MY_var1 = (uint16_t) CONST1;