10.2.3 Amplification

[hahn]

Thanks for your reply and the clarifications.
I have one more code example which reading the text appears non-compliant to me, but does not contradict the rationale or poses an issue in my view.

Code:

enum E e;
  E& eref = e; // Compliant or not?

There is a source of an assignment (variable initialization) of enum type, and the target type (E&) is neither the same enum type (but reference to it) or a sufficiently sized integer type.

A clarification once more would be great.