A13-5-4 opposite operator clarification

[misra cpp]

Answering your questions in order:
- Yes, your code is compliant - we're not quite sure how you came to the conclusion we were expecting <= to be implemented with >=
- Yes, as in your example the implementation of <= can use >
- The rule applies to three pairs: == & != <= & > >= & <

A possible compliant implementation would be to define == and < and use std::rel_ops